Vectors Calaulus 1.8

The Unit Tangent and the Unit Normal  Vectors   The Unit Tangent Vector The derivative of a vector valued function gives a new vector valued function that is tangent to the defined curve.  The analogue to the slope of the tangent line is the direction of the tangent line.  Since a vector contains a magnitude and a direction, the velocity vector  contains more information than we need.  We can strip a vector of its magnitude by dividing by its magnitude.     Definition of the Unit Tangent Vector   Let r(t) be a differentiable vector valued function and v(t) = r'(t) be  the velocity vector.  Then we define the unit tangent vector by as the  unit vector in the direction of the velocity vector.                                  v(t)                T(t)  =                                                      ||v(t)||   Example Let          r(t)  =  t i + et j - 3t2 k Find the T(t) and T(0). Solution We have          v(t)  =  r'(t)  =  i + et j - 6t k and          To find the unit tangent vector, we just divide         To find T(0) plug in 0 to get           The Principal Unit Normal Vector         A normal vector is a perpendicular vector.  Given a vector v in the space, there are infinitely many perpendicular vectors.  Our goal is to select a special vector that is  normal to the unit tangent vector.  Geometrically, for a non straight curve, this vector is the unique vector that point into the curve.  Algebraically we can compute the vector using the following definition.   Definition of the Principal Unit Normal Vector Let r(t) be a differentiable vector valued function and let T(t) be the unit tangent vector.  Then the principal unit normal vector N(t) is defined by                                  T'(t)                N(t)  =                                                      ||T'(t)|| Comparing this with the formula for the unit tangent vector, if we think of the unit tangent vector  as a vector valued function, then the principal unit normal vector is the unit tangent vector of the unit tangent vector function.  You will find that finding the principal unit normal vector  is almost always cumbersome.  The quotient rule usually rears its ugly head.   Example Find the unit normal vector for the vector valued function         r(t)  =  ti + t2 j  and sketch the curve, the unit tangent and unit normal vectors when t = 1. Solution First we find the unit tangent vector         Now use the quotient rule to find T'(t)         Since the unit vector in the direction of a given vector will be the same after multiplying the  vector by a positive scalar, we can simplify by multiplying by the factor         The first factor gets rid of the denominator and the second factor gets rid of the fractional power.   We have         Now we divide by the magnitude (after first dividing by 2) to get          Now plug in 1 for both the unit tangent vector to get                     The picture below shows the graph and the two vectors.               Tangential and Normal Components of Acceleration Imagine yourself driving down from Echo Summit towards Myers and having your brakes fail.   As you are riding you will experience two forces (other than the force of terror) that will change the velocity.  The force of gravity will cause the car to increase in speed.  A second change in  velocity will be caused by the car going around the curve.  The first component of acceleration is called the tangential component of acceleration and the second is called the   normal component of acceleration.  As you may guess the tangential component of acceleration is in the direction of the unit tangent vector and the normal component of  acceleration is in the direction of the principal unit normal vector.  Once we have   T and N, it is straightforward to find the two components.  We have   Tangential and Normal Components of Acceleration The tangential component of acceleration is                 and the normal component of acceleration is                 and                    a   =   aNN + aTT Proof First notice that          v  =  ||v|| T        and        T'  =  ||T'|| N Taking the derivative of both sides gives         a  =  v'  =  ||v||' T + ||v|| T'  =  ||v||' T + ||v|| ||T' || N  This tells us that the acceleration vector is in the plane that contains the unit tangent vector  and the unit  normal vector.  The first equality follows immediately from the definition of the component of a vector in the direction of another vector.  The second equalities will be left as exercises. Example  Find the tangential and normal components of acceleration for the prior example                 r(t)  =  ti + t2 j  Solution Taking two derivatives, we have         a(t)  =  r''(t)  =  2j We dot the acceleration vector with the unit tangent and normal vectors to get